Respuesta :

carlosego
The generic equation of the circle is:
 (x-xo) ^ 2 + (y-yo) ^ 2 = r ^ 2
 Where,
 (xo, yo): coordinate of the center of the circle
 r: radius of the circle.
 Substituting values we have:
 (x-9.2) ^ 2 + (y + 7.4) ^ 2 = (5/3) ^ 2
 Rewriting:
 (x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
 Answer:
 The equation of the circle is:
 (x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
aencabo
r = 5/3
C(9.2, -7.4)

r^2 = (x-h)^2 + (y-k)^2
(5/3)^2 = (x - 9.2)^2 + (y + 7.4)^2

Otras preguntas