The solutions to the given quadratic equation can be determined using quadratic formula.
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b =coefficient of x term = -2
a = coefficient of squared term = 1
c = constant term = 10
Using the values in the above formula we get:
[tex]x= \frac{2+- \sqrt{4-4(1)(10)} }{2(1)} \\ \\
x= \frac{2+- \sqrt{-36} }{2} \\ \\
x= \frac{2+-6i}{2} \\ \\
x=1+3i, x=1-3i [/tex]
So the correct answer to this question is option A
