kylamchavez
kylamchavez
03-03-2018
Mathematics
contestada
find the roots of the equation x3-3x^2+x+5
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Professor1994
Professor1994
03-03-2018
x^3-3x^2+x+5=(x+1)(x^2-4x+5)
(x+1)(x^2-4x+5)=0
x+1=0→x+1-1=0-1→x=-1
x^2-4x+5 different to zero
The root of the equation is x=-1
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