Respuesta :

[tex]\bf \begin{cases} f(x)=-5x+1\\ g(x)=x^3\\ (g\circ f)(x)=g(~~f(x)~~) \end{cases} \\\\\\ f(0)=-5(0)+1\implies \boxed{f(0)=1} \\\\\\ g(~~f(x)~~)\implies g(~~f(0)~~)\implies g\left( ~~\boxed{1}~~ \right)=(1)^3\implies g(1)=1[/tex]

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