The sum of the arithmetic series given is
2+5+8+ ... + 59
The first term is a₁ = 2
The common difference is d = 5-2 = 3
The n-th term is a₁ + (n-1)d
Therefore the last term is given by
2 + 3(n-1) = 59
3(n-1) = 57
n-1 = 19
n = 20
The sum of n terms is
[tex]S_{n} = \frac{n}{2}(a_{1} + a_{n} ) [/tex]
Therefore the sum of the series is
[tex] \frac{20}{2}(2+59) = 610 [/tex]
Answer: 610
