You have to find the reaction involving sodium iodide and ozone or O₃. If you search in the internet, the reaction would be
O₃(g) + 2 NaI(aq) + H₂O(l) → O₂(g) + I₂(g) + 2 NaOH(aq)
Using the stoichiometric coefficients in the reaction, the solution would be
5.95×10⁻⁶ mol O₃ * (2 mol NaI/1 mol O₃) = 1.19×10⁻⁵ mol NaI
