Answer:
[tex]\text{S.A.S. postulate}[/tex]
Step-by-step explanation:
[tex]\text{In triangles NPM and OMP,}\\\text{i. NP = OM (S) [Given]}\\\text{ii. }\angle \text{NPM}=\angle \text{OMP (A)\ \ \ [Given]}\\\text{iii. }\text{PM = PM (S) \ \ \ \text{[Common sides of both triangles.]}}\\\text{iv. }\triangle \text{NPM}\cong\triangle \text{OMP}\ \ \ [\text{By S.A.S. postulate.}][/tex]
