Respuesta :

dashataran

Answer:

[tex]6\times5^{28[/tex]

Step-by-step explanation:

[tex]\text{Here,}\\\text{First term}(a)=6\\\text{Common ratio}(r)=\text{Second term}/\text{First term}=30/6=5\\\text{We have,}\\\text{nth term}(t_n)=ar^{n-1}[/tex]

[tex]\text{Now,}\\\\\text{29th term}(t_{29})=ar^{29-1}=6\times5^{28}[/tex]

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