[tex]7x-2y> 8 \ \ -7x \\ \\7x -7x-2y> 8 -7x \\ \\ -2y >8-7x \ \ / : (-2)\\ \\\frac{-2}{-2}\cdot y < \frac{8}{(-2)}-\frac{7}{(-2)}x \\ \\ y < \frac{7}{ 2}x -4 \\ \\ \\ Answer : \ c) \ y < \frac{7}{2}x-4[/tex]
[tex]If \ we \ multiply \ or \ divide \ both \ sides \ of \ an \ inequality \ by \ a \ negative \\ \\number \ we \ have \ to \ switch \ the \ direction \ of \ the \ inequality[/tex]
