camoo11
camoo11 camoo11
  • 03-04-2017
  • Mathematics
contestada

what's the solution to 20+2x<5x+17-3x

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Аноним Аноним
  • 03-04-2017
1 Simplify 5x+17-3x to 2x+17

20+2x<2x+17

2 Cancel 2x on both sides.

20<17

3 Since 20<17 is false, there is no solution
No solution. :)

I hope this helps you understand! :D

Have a great day by the way.





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ItsLeviosaaa
ItsLeviosaaa ItsLeviosaaa
  • 03-04-2017
Treat it like an equation, you'll do a simple two-step rearrangement:
20+2x < 5x +17-3x -> 20+2x < 2x+17 -> 3+2x < 2x -> 3 < 0x. Now at this point in solving we run into a problem... nothing times 0 can be greater than 3, so this is undefined
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