Use the next trigonometric ratio to find the value of x:
[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]
For angle x:
[tex]\begin{gathered} sinx=\frac{9}{29} \\ \\ x=\sin^{-1}(\frac{9}{29}) \\ \\ x\approx18º \end{gathered}[/tex]Then, the value of x is 18º
