Solution
We are given the equation
[tex]x^2+10xy+25y^2-2x-4y+10=0[/tex]
We will first simplify the equation
[tex]\begin{gathered} x^{2}+10xy+25y^{2}-2x-4y+10=0 \\ \left(x+5y\right)^2-2\left(x+y\right)+10=0 \\ (x+5y)^2=2(x+y)-10 \end{gathered}[/tex]
We draw the graph
From the graph, one can see that this is a rotated parabola
Correct answer is a Parabola
Option A
