Notice that:
[tex]\begin{gathered} 2=2\times3^0, \\ 6=2\times3^1, \\ 18=2\times3^2, \\ 54=2\times3^3. \end{gathered}[/tex]Therefore, the rule to compute the nth term of the sequence is:
[tex]a_n=2\times3^{n-1}.[/tex]Substituting n=13 in the above equation we get:
[tex]a_{13}=2\times3^{13-1}=2\times3^{12}=1062882.[/tex]Answer: 1062882.
