Given the equation of a straight line below
[tex]y=-\frac{4}{3}x+\frac{4}{3}[/tex]
The general equation of a line,
[tex]y=mx+c_{}[/tex]
Where
[tex]\begin{gathered} m\text{ is the slope of the line} \\ c\text{ is the y-intercept} \end{gathered}[/tex]
The slope, m, of the given line is
[tex]m=-\frac{4}{3}[/tex]
The graph of the equation of the line given is shown below
Hence, the slope of the given equation of a line is, m = -4/3
