To finde the equation of the line troughh the points (0;0) and (-8;-5) first you must find the slope of the line. You have to use the next formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
Replacing the points in the previous formula
[tex]m=\frac{-5-0}{-8-0}=\frac{5}{8}[/tex]
As the line passes trough the origin of coordinates (point (0;0)) the equation is:
[tex]y=\frac{5}{8}x[/tex]
So the answer is y= 5/8 x (option B)
