According to the chemical equation one mol of (NH4)2CO3 produces 2 mol of NH3
[tex](NH_4)_2CO_3\Longrightarrow2NH_3+CO_2+H_2O[/tex]
When expresed in mass 96.09 grams of (NH4)2CO3 produce 34 grams of NH3 when we keep this proportion for the 5 grams we obtain:
[tex]5gof(NH_4)_2CO_3\text{ }\frac{34gofNH_3_{}}{96.09\text{ g of}(NH_4)_2CO_3\text{ }}=1.76gofNH_3[/tex]
