Step 1: Write out the equation
[tex]x^2-12x+32=4[/tex]
Step 2: Subtract 32 from both sides of the equation
[tex]\begin{gathered} x^2-12x+32-32=4-32 \\ x^2-12x=-28 \end{gathered}[/tex]
Step 3: Complete the square by adding 1/2 of the square of the coefficient of x to both sides
That is
[tex]x^2-12x+(-6)^2=-28+(-6)^2[/tex]
This implies that
[tex](x-6)^2=-28+36=8[/tex]
Hence the intermediate step is (x - 6)² = 8
