Question:
Solution:
Let the following equation:
[tex]\sqrt[]{12-x}=\text{ x}[/tex]
this is equivalent to:
[tex](\sqrt[]{12-x})^2=x^2[/tex]
this is equivalent to:
[tex]12-x=x^2[/tex]
this is equivalent to:
[tex]x^2+x-12=\text{ 0}[/tex]
thus, we can conclude that
x= 3.
