Okay, here we have this:
Considering the provided equation, we are going to solve it, so we obtain the following:
[tex]\begin{gathered} -3-7i+6x=19+2i+13yi \\ (-3+6x)-7i=19+(2+13y)i \end{gathered}[/tex]
So let's remember that a set of complex numbers can only be equal if their real and imaginary parts are equal. According to this we have:
-3+6x=19, -7=2+13y
6x=19+3, -7-2=13y
6x=22, -9=13y
x=22/6, y=-9/13
x=11/3, y=-9/13
Finally we obtain the following set: x=11/3, y=-9/13.
