-2x² - 6x + 15 = 2x +5
Re-arrange the equation
-2x² - 6x -2x+ 15-5=0
-2x² -8x + 10 = 0
Multiply through by negative one
2x² + 8x - 10 =0
Now;
solve by factorization
Find two numbers such that its product give -20x² and its sum gives 8x and 8x by them
That is;
2x² + 10x - 2x - 10 = 0
2x(x+5) -2(x+5) = 0
(2x - 2) (x+5) = 0
Either 2x - 2 = 0
2x = 2
x= 1
Or
x+5 = 0
x=-5
Hence it has 2 real solutions
