YashviB744386 YashviB744386
  • 03-11-2022
  • Mathematics
contestada

[tex] \sqrt[3]{80} [/tex]simplify in simplest radical form

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BrynnenI628333 BrynnenI628333
  • 03-11-2022

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

[tex]\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}[/tex]

rewrite the root

[tex]\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}[/tex]

then cancel the terms that are cubes and bring them out of the root

[tex]\sqrt[3]{80}=2\sqrt[3]{10}[/tex]

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