[tex]\begin{gathered} \int_{\text{ -}1}^2e^{x^2}=\frac{h}{2}(e^{(\text{ -1\rparen}^2}+e^{2^2}) \\ \\ h=(b\text{ - }a)/n=(2\text{ - \lparen-1\rparen\rparen/4=}\frac{3}{8}\text{ } \\ \int_{\text{ -1}}^2e^{x^2}=\frac{3}{8}(e+2e^{\frac{1}{16}}+2e^{\frac{1}{4}}+2e^{\frac{25}{16}}+e^4) \\ \\ =\frac{3}{8}(2.72+2.13+2.57+9.54+54.6) \\ \\ =\frac{3}{8}(71.56)=26.84 \end{gathered}[/tex]
