We hve the equation
[tex]x^2+4x-9=x+1[/tex]
We are to find the value of x
Solving the equation we have
[tex]\begin{gathered} x^2+4x-9=x+1 \\ x^2+4x-x-9-1=0 \\ x^2+3x-10=0 \end{gathered}[/tex]
Factorising the equation further
[tex]\begin{gathered} x^2+3x-10=0 \\ x^2+5x-2x-10=0 \\ x(x+5)-2(x+5)=0 \\ (x+5)(x-2)=0 \\ x+5=0,x-2=0 \\ x=-5,x=2 \end{gathered}[/tex]
Therefore the solution to the equation is -5 and 2
