Given that line, AD is the same as line CB, and angle B and angle D are right angles
To Prove: triangle ADC is congruent to triangle CBA
Solution
[tex]\angle D,and,\angle B,are\text{ right angles====(Given)}[/tex][tex]\Delta ADC,and,\Delta CBA,are\text{ right triangles ===(definition of right triangle)}[/tex][tex]AC\cong AC====(reflexive\text{ property of congruence)}[/tex][tex]AD\cong CB====(given)[/tex][tex]\Delta ADC\cong\Delta CBA====(HL)[/tex]
