Solution
We are given
[tex]y=4x^2+15x-4[/tex]
Here
[tex]\begin{gathered} a=4 \\ b=15 \\ c=-4 \end{gathered}[/tex]
The discriminant D is
[tex]\begin{gathered} D=b^2-4ac \\ D=15^2-4(4)(-4) \\ D=225+64 \\ D=289 \end{gathered}[/tex]
Since, the discriminant is positive, we have two x- intercept
