Answer:
[tex]R\text{ =}\sqrt[3]{\frac{9V}{4\pi}}[/tex]Explanation:
Here, we want to solve the formula for r
That means we have to make r the subject of the formula
We have that as follows:
[tex]\begin{gathered} V\text{ = }\frac{4}{9}\times\pi\times R^3 \\ \\ R^3\text{ = }\frac{9V}{4\pi} \\ \\ R\text{ = }\sqrt[3]{\frac{9V}{4\pi}} \end{gathered}[/tex]