Given
The expression is given as
[tex]x(0.01+x)=3.2\times10^{-7}[/tex]
Explanation
To determine the value of x,
[tex]\begin{gathered} 0.01x+x^2=3.2\times10^{-7} \\ x^2+0.01x-3.2\times10^{-7}=0 \end{gathered}[/tex]
Now apply the quadratic formula.
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Substitute the values.
[tex]x=\frac{-0.01\pm\sqrt{0.01^2-4\times1\times(-3.2\times10^{-7})}}{2}[/tex]
Solving the equation we get,
x=-0.01003,0.00003.
Answer
Hence the value of x are
[tex]x=-0.01003,x=0.00003[/tex]
