The given equation is:
[tex]e^m=s[/tex]
Take the natural log of both sides:
[tex]\ln e^m=\ln s[/tex]
Apply the power rule of logarithms:
[tex]\begin{gathered} m\ln e=\ln s \\ Also\text{ }\ln e=1,\text{ then} \\ m*1=\ln s \\ m=\ln s \\ \text{ Reorder terms} \\ \ln(s)=m \end{gathered}[/tex]
The answer is B. ln(s)=m
