Answer:
[tex]\boxed{\sf 1\dfrac{1}{6}\ liters \ of \ water}[/tex]
Explanation:
Let the total water required water the entire ground be g
Equation:
[tex]\sf \dfrac{2}{7}\:g = \dfrac{1}{3} \ liters \ of \ water[/tex]
rearranging
[tex]\sf g = \dfrac{7(1)}{3(2)}[/tex]
simplify
[tex]\sf g = \dfrac{7}{6} \ liters \ of \ water[/tex]
rewrite in mixed fraction
[tex]\bf g = 1\dfrac{1}{6}\ liters \ of \ water[/tex]
The water required to water the entire ground is 1 1/6 liters.
