Answer:
[tex]x=-8, -1[/tex]
Step-by-step explanation:
Given the equation [tex]x^{2} +9x+8=0\\[/tex],
By the quadratic formula,
[tex]x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex],
[tex]x=\frac{-(9)+-\sqrt{(9)^{2}-4(1)(8) } }{2(1)}=\frac{-9+-\sqrt{49 } }{2}=\frac{-9+-7 }{2}[/tex]
We have two different solutions for x where [tex]x=\frac{-9-7 }{2}[/tex] and [tex]x=\frac{-9+7 }{2}[/tex]
So, x = [tex]-16/2=-8[/tex] and [tex]x=-2/2=-1[/tex]
Therefore, the solutions to this quadratic equation is x = -8, -1, by the quadratic formula.
