evaluate (-4+i)(-4-i)

I get to
16+4i-4i-i^2

But I'm a little confused, please help!!

Question

02-02-2017
Mathematics

contestada

evaluate (-4+i)(-4-i)

I get to
16+4i-4i-i^2

But I'm a little confused, please help!!

Respuesta :

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Gidwn Gidwn · Answer 1 · 2017-02-02T04:25:16+01:00

Gidwn Gidwn

02-02-2017

I get 16-i^2... So you basically distribute everything.
So first, you'd do -4(-4-i) which gets you 16+4i
Next, you do i(-4-i) which gets you -4i-i^2
When you add like terms, (-4i+4i), you're left with 16-i^2.
So 16-i^2 would be your answer.

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evaluate (-4+i)(-4-i) I get to 16+4i-4i-i^2 But I'm a little confused, please help!!

Respuesta :

Otras preguntas

evaluate (-4+i)(-4-i)

I get to
16+4i-4i-i^2

But I'm a little confused, please help!!