Step-by-step explanation:
group like terms
[tex]3w \geqslant 19 - 1[/tex]
solve
[tex]3w \geqslant 18[/tex]
divide the number with the variable by both sides
[tex] \frac{3w}{3} \geqslant \frac{18}{3} [/tex]
[tex]w \geqslant 6[/tex]
Answer:
w ≥ 6
Given:
3w+1≥19
Solve:
Subtract 1 from both sides
-1 -1
-----------------
3w≥18
Divide both sides by 3
3w/3 ≥18/3
Hence, the answer is:
Kavinsky
