Answer:
Step-by-step explanation:
[tex]xy=5, y=-2x-8[/tex]
Using substitution,
[tex]x(-2x-8)=-5\\-2x^{2}-8x=-5\\2x^{2}+8x-5=0\\x=\frac{-8 \pm \sqrt{8^{2}-4(2)(-5)}}{4}\\x=\frac{-8 \pm \sqrt{104}}{4}\\x=-2 \pm \sqrt{13/2}[/tex]
So, if [tex]x=-2+\sqrt{13/2}[/tex], y=[tex]-2(-2+\sqrt{13/2})-8=4-\sqrt{26}[/tex]
And if [tex]x=-2-\sqrt{13/2}[/tex], [tex]y=-2(-2-\sqrt{13/2})=\sqrt{26}-4[/tex]
