Answer:
n=35; q=33 coins.
Step-by-step explanation:
1) if number of nickles is 'n' and the quaters is 'q' then it is possible to write:
n+q=68 - 'she counted 68 coins...' - the 1st equation of system;
0.25q+0.05n=10 - '10$ in it' - the 2d equation of the system.
2) it is possible to make up and solve the next system of two equations:
[tex]\left \{ {{q+n=68} \atop {0.25q+0.05n=10}} \right. \ => \ \left \{ {{q=33} \atop {n=35}} \right. .[/tex]
