[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: {x}^{2} = 49 [/tex]
According to rule : x² = y, then x = ± √y
[tex]\qquad \sf \dashrightarrow \: x = \pm\sqrt{49} [/tex]
[tex]\qquad \sf \dashrightarrow \: x= \pm7[/tex]
