Answer:
[tex] {12}^{2x - 1} = ( \sqrt[4]{12} )x \\ \\ {12}^{2x - 1} = ( {12}^{ \frac{1}{4} } )x \\ \\ {12}^{2x - 1} = {12}^{ \frac{x}{4} } \\ \\ 2x - 1 = \frac{x}{4} \\ \\ 2x \times 4 - 4 = \frac{x + 4}{4} \\ \\ 2x \times 4 - 4 = x \\ \\ 8x - 4 = x \\ \\ 8x - x = 4 \\ \\ 7x = 4 \\ \\ x = \frac{7}{4} \\ \\ x = 3.5[/tex]
