The IUPAC name of the compound is cesium hydrogen trioxosulfate IV.
We can see that the central atom in this compound is sulfur. We have to deduce its oxidation state as follows;
1 + 1 + x + 3(-2) = 0
2 + x - 6 = 0
x = 4
Recall that in writing the IUPAC name of a compound the oxidation state of the central atom is written after the name of the atom.
Hence, the compound is cesium hydrogen trioxosulfate IV.
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