Answer:
0
Step-by-step explanation:
i^1 = i
i^2 = - 1
i^3 = i^2 * i = - 1
i^4 = i^2 * i^2 = -1 * -1 = 1
Now the circle just repeats itself. So what you do is find out the remainder of i^97 which you divide by 4. What you get is 24 with a remainder of 1.
So i^97 = i
i - i = 0
The answer is 0
