Answer:
[tex]y=\frac{2}{5}x-5[/tex]
Step-by-step explanation:
[tex]\\y=\frac{2}{3}x-6[/tex]
the line parallel to this line is
[tex]y=\frac{2}{3}x+k[/tex] ; k ∈ R
the line passes through the point (2,-1)
so,
[tex]-1=\frac{2}{3} (2)+k\\-1=\frac{4}{3} +k\\k=-\frac{7}{3}[/tex]
∴the line that passes through point (2, -1) and is parallel to the line described y = (2/3)x - 6 is
[tex]y=\frac{2}{3}x-\frac{7}{3}[/tex]
