Answer:
Step-by-step explanation:
r =term 1 ÷ term 2 = 1 ÷ 3 = 1/3
a =term 1 = 3
n = 5
[tex]Sum = \frac{a(1-r^{n})}{1-r}[/tex]
[tex]= \frac{3*(1-(\frac{1}{3})^{5}}{1-\frac{1}{3}}\\\\=\frac{3*(1-\frac{1}{243})}{\frac{2}{3}}\\\\=\frac{3*\frac{242}{243}}{\frac{2}{3}}\\\\=3*\frac{242}{243}*\frac{3}{2}\\\\=\frac{121}{27}\\\\=4 \frac{13}{27}[/tex]
