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Answer:
B. log_b(a) - log_b(d)
Step-by-step explanation:
The applicable rule of logarithms is ...
log(a/b) = log(a) -log(b)
All the logs need to have the same base.
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Here, the base is 'b', but the rule still applies:
[tex]\log_b{\dfrac{a}{d}}=\log_b{(a)}-\log_b{(d)}[/tex]
