Answer:
H=MC∆T
Heat = Heat absorbed or given off
M=Mass
C=Specific Heat Capacity of substance (Water in thus case). It has a Specific Heat capacity of 4200J/kg.k
∆T= Temp Change (T2-T1)
I'll solve with My Heat in Joules.
The heat is given in Calorie
1Cal = 4.186J
2500cal = 10,465J.
∆T= H/MC
=10465/0.15(4200)
=16.6°C
∆T=16.6
T2 - T1 = 16.6
T2 = 16.6+T1
T2 = 16.6 + 23
T2 = 39.6
Approx. 40°C
