Respuesta :
[tex](y + 1)(y + 12)[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] {y}^{2} + 13y + 12 \\ = {y}^{2} + 12y + 1y + 12 \\ taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\ = (y + 1)(y + 12)[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
