Answer:
When object falls freely we can say
its initial speed will be ZERO
and its acceleration due to gravity must be
a = g = 9.8 m/s^2a=g=9.8m/s2
Now we need to find the distance of free fall in 3 s of time
So here we will use kinematics
y = v* t + \frac{1}{2} at^2y=v∗t+21at2
now we will plug in all values in it
y = 0 + \frac{1}{2}* 9.8 * 3^2y=0+21∗9.8∗32
y = 44.1 my=44.1m
So it will fall by total distance of 44.1 m
