Answer:
–1
Step-by-step explanation:
We want to find the following limit:
[tex]\lim_{x \rightarrow -2} x^3 + 3x^2 - 5[/tex]
Since the function does not have any discontinuity(point in which the denominator is 0, for example), we just replace the values of x by -2. So
[tex]\lim_{x \rightarrow -2} x^3 + 3x^2 - 5 = (-2)^3 + 3(-2)^2 - 5 = -8 + 12 - 5 = -13 + 12 = -1[/tex]
The value of the limit is -1.
