Answer:
Q = 768.47 J
Explanation:
Given that,
Mass of the metal, m = 25 g
Initial temperature, T₁ = 21.0 ºC
Final temperature, T₂ = 80.0 ºC
The specific heat of the metal is 0.521 J/gºC.
We know that the heat released due to the change in temperature is given by :
[tex]Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J[/tex]
Hence, 768.47 J of heat energy will be needed.
