Answer:
Force of 37.8 × 10^(6) N attracts the two charges
Explanation:
The force between two charges is given by
F = k*q1*q2/r²
Where q1 and q2 are 0.06 C and 0.07 C.
r is the distance between q1 and q2 which is equal to 3 m
k is a constant = 9 × 10^(9) N.m²/C²
F = (9 × 10^(9) × 0.06 × 0.07)/3²
F = 37.8 × 10^(6) N
