Answer:
[tex]x=\sqrt{10}[/tex]
Step-by-step explanation:
For first right angled tringle,
Hypotenuse = 10
Height = 9
We can find the base of first triangle using Pythagoras therorem,
[tex]b=\sqrt{10^2-9^2}\\\\=\sqrt{100-81}\\\\=\sqrt{19}[/tex]
Now, for other triangle,
Height = 3
Hypotenuse = [tex]\sqrt{19}[/tex]
So,
[tex]x=\sqrt{(\sqrt{19})^2-3^2}\\\\=\sqrt{19-9}\\\\=\sqrt{10}[/tex]
So, the value of x is equal to [tex]\sqrt{10}[/tex].
