Answer: 5.39g/L
Explanation:
We need to calculate the average molar mass of the mixture which will be:
= (10 × 32) + (50 × 40) + (40 × 244) / 100
= (320 + 2000 + 9760) / 100
= 12080 / 100
= 120.8g/mol
Since the volume occupied is 22.4L and 1 mole of the gas will occupies 22.4L given the standard temperature conditions, then the density of the mixture will be:
= Mass / volume
= 120.8 / 22.4
= 5.39g/L
Therefore, the density of the mixture will be 5.39g/L.
