Answer:
Q = 63.9 kJ
Explanation:
Given that,
Mass of ice, m = 300 g
We need to find the heat needed to heat the given amount of ice at -5.00°C into steam at 100.°C
The specific heat of ice, c = 2.03 J/g °C
The formula for heat needed is given by :
[tex]Q=mc\Delta T\\\\Q=300\times 2.03\times (100-(-5))\\\\Q=63945\ J\\\\Q=63.9\ kJ[/tex]
So, 63.9 kJ of heat is needed.
